Physics, asked by KSEH5163, 1 year ago

A 4kg object is moving horizontaly with aspeed of 5m/s to increas its speed to 10m/s the amount of net work is done

Answers

Answered by student235

By applying work energy theorm,
Sum of work done by all forces = change in kinetic energy
therefore, 1/2 * 4* {(10)^2 - (5)^2} = 150 Joules
Hope it helps.

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