Question

A 4kg object is moving horizontaly with aspeed of 5m/s to increas its speed to 10m/s the amount of net work is done

Answer 1

By applying work energy theorm,
Sum of work done by all forces = change in kinetic energy
therefore, 1/2 * 4* {(10)^2 - (5)^2} = 150 Joules
Hope it helps.