A 4kW electric heater is connected to a 220V source of power. The
amount of energy consumed in 2 hrs is ...
8 unit
4 unit
16 unit
2 unit
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Power = 4KW = 4000 W Volt = 220 Electric power , P=VI (I)After putting values, I = 18.18 A (II)R denotes resistance here ,V= IR R= V/ I= 220 V/ 18. 18 A= 12. 1012 ohm. (III) Power= 4000 W= 4000 J/ s So, in 2 hours energy in kWh is = 4000J/ s * 3600 * 2/( 3600000)= 8 kWh
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