Question

A 4m long wire has 1.2 cm cross sectional area. It is stretched by a force a 4.8 x 10 newton. Calculate the stress and increase in length of wire given Y = 1.2 X 10 N/M2​

Answer 1

Answer:

A 4 m long copper wire of cross-sectional area 1.2 cm2 is stretched by a force of 4.8 x 103 N. Young's modulus for copper is Y = 1.2 x 1011 N/m2, the increase in length of the wire is. 1.32 mm. 0.8 mm.

Answer 2

Explanation:

Solution below

the solution is in the pic given below

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