Question

A 4m long wire has 1.2 cm² cross sectional area it is stretched by a force of 4.8×10³ N .calculate the stress and increasing length .
​

Answer 1

Explanation:

Young's modulus, Y=

strain

stess

=

Δl/l

F/A

=

AΔl

Fl

So, increase in length Δl=

AY

Fl

=

(1.2×10

−4

)(1.2×10

11

)

(4.8×10

3

)(4)

=1.33×10

−3

m=1.33mm