Question

A 4ohm resistance is doubled. Calculate the new resistance of the wire

Answer 1

♣️HEYA ‼️‼️

✴️A N S W E R I S H E R E ✴️



We consider wire is doubled on it means to fold the length of wire. It means its length will get half and area of cross section will get doubled.

∴ Let the resistance of the wire originally 'R' of length 'L' and area of cross-section 'A' with resistivity of material is 'p',

Then

R = p l/A = 4Ω

Now, for new arrangement,

p' = p

l' = l / 2

A' = 2A

Thus, 

R' = p' l'/A' = p (l /2) ÷ 2A = !/4 (p l / A) = 1/4R = 1/4 × 4 = 1Ω.

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H o P E T H I S H e L P S ♣️♣️

Answer 2

WHEN THE WIRE IS DOUBLED THE LENGTH

WILL BE HANDED AND AREA WILL BE DOBLE

R = PL/A ...i

R' = P( L/2 ) / 2A. ...ii

DIVIDE EQUATION ii ÷ i

R'/R = PL / 4A / PL / A

R' / R = ¼

R' = R/4

R' = 1Ω

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