a. 4x2 + 12xy + 9y2
b. 9a2 – 24ab + 16b2
c. p2q2 – 6pqr + 9r2
d. 36a2 + 36a + 9
e. 4 – 6x + 81x2
f. 4x2+ 2x + 1/4
g. 36x2– 4xy + 1/9y2
h. 16x2 – 25y2
i. 27x2 – 12y2
j. 3a5 – 48a3
k. (2a – b)2 – 16c2
l. (x + 2y)2 – 4 (2x – y)2
m. 64 – (a + 1)2
n. a4 – 1/b4
o. 1/16x2y2 – 4/49y2z2
facrorize them
Answers
Answer:
a clear explanation
there are 3 method to factorisation
1. formula method
2.taking common value
3.i method
if you find last number and first number square then change to square number like this 4 is 2
a.formula method: =(2x)^2+2(2x)(3y)+(3y)^2.
after this step you should take first and laste bracket value and I bolded one value up before that number -or+came you should put same integer in the place I bolded down
=(2x + 3y)^
after this you should double the bracket value
=(2x+3y)(2x+3y)
the formula I used is (a+b)^2
if last and first number is in square then we should use formula method
b.this is also formula method.the formula we should use is (a-b)^2.u can try
c.formula method:=(pq)^2-2(pq)(3r)+(3r)^2
=(pq-3r)^2
=(pq-3r)(pq-3r)
the formula I used is (a-b)^2
d.this is also formula method:(6a)^2+2(6a)(3)+(9)
=(6a+3)^2
=(6a+3)(6a+3)
the formula I used is (a+b)^2
I will give you hint using this example you can finish
e. you can use formula method 4 is 2hole square and 81x2 is 9x the hole square. the formula to calculate is(a-b)^2
f.the formula to calculate is(a+b)^2
1/4 is 1/(2)^2
g.the formula to calculate is(a-b)^2.1/9 is 1/(3)^2
h.(a2-b2)=(a+b)(a-b)
h.(a2-b2)=(a+b)(a-b)(4x)^2-(5y)^2
h.(a2-b2)=(a+b)(a-b)(4x)^2-(5y)^2(4x+5y)(4x-5y)
I . also same like this square the value
j3a5 – 48a3take commen value out ( the common value is a and 3)
k .l.m.the formula to calculate is(a2-b2)=(a+b)
n .a4-1/b4
(a^2)^2-1/(b^2)^2
then substitute
hope it helps you
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