Math, asked by tahiraahsan, 9 months ago

a. 4x2 + 12xy + 9y2
b. 9a2 – 24ab + 16b2
c. p2q2 – 6pqr + 9r2
d. 36a2 + 36a + 9
e. 4 – 6x + 81x2
f. 4x2+ 2x + 1/4
g. 36x2– 4xy + 1/9y2
h. 16x2 – 25y2
i. 27x2 – 12y2
j. 3a5 – 48a3
k. (2a – b)2 – 16c2
l. (x + 2y)2 – 4 (2x – y)2
m. 64 – (a + 1)2
n. a4 – 1/b4
o. 1/16x2y2 – 4/49y2z2
facrorize them

Answers

Answered by vihasinimohanraj
0

Answer:

a clear explanation

there are 3 method to factorisation

1. formula method

2.taking common value

3.i method

if you find last number and first number square then change to square number like this 4 is 2

a.formula method: =(2x)^2+2(2x)(3y)+(3y)^2.

after this step you should take first and laste bracket value and I bolded one value up before that number -or+came you should put same integer in the place I bolded down

=(2x + 3y)^

after this you should double the bracket value

=(2x+3y)(2x+3y)

the formula I used is (a+b)^2

if last and first number is in square then we should use formula method

b.this is also formula method.the formula we should use is (a-b)^2.u can try

c.formula method:=(pq)^2-2(pq)(3r)+(3r)^2

=(pq-3r)^2

=(pq-3r)(pq-3r)

the formula I used is (a-b)^2

d.this is also formula method:(6a)^2+2(6a)(3)+(9)

=(6a+3)^2

=(6a+3)(6a+3)

the formula I used is (a+b)^2

I will give you hint using this example you can finish

e. you can use formula method 4 is 2hole square and 81x2 is 9x the hole square. the formula to calculate is(a-b)^2

f.the formula to calculate is(a+b)^2

1/4 is 1/(2)^2

g.the formula to calculate is(a-b)^2.1/9 is 1/(3)^2

h.(a2-b2)=(a+b)(a-b)

h.(a2-b2)=(a+b)(a-b)(4x)^2-(5y)^2

h.(a2-b2)=(a+b)(a-b)(4x)^2-(5y)^2(4x+5y)(4x-5y)

I . also same like this square the value

j3a5 – 48a3take commen value out ( the common value is a and 3)

k .l.m.the formula to calculate is(a2-b2)=(a+b)

n .a4-1/b4

(a^2)^2-1/(b^2)^2

then substitute

hope it helps you

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