A=4y+20°
b =[3 Y - 5] °
c = [-4x° ]
D= (7 x + 5 )°
find the angles of cyclic quadrilateral
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In quadrilateral ABCD,
∠A+∠C=180°
⇒4y+20−4x=180°
−4x+4y=160°
⇒−x+y=40°
⇒−3x+3y=120°→1
∠B+∠D=180°
3y−5+7x+5=180°
7x+3y=180°→2
Solving equation 1 and 2, we get
7x+3y+3x−3y=180°−120°⇒10x=60°⇒x=6
& −6+y=40°⇒y=46°
∴∠A=4×46°+20=204°,∠B=3×46−5=133°
∠C=−4×6=−24°,∠D=7×6+5=47°
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