Question

A 5.0-g sample of Substance X increases in temperature from 20.0mc005-1.jpgC to 22.0mc005-2.jpgC when it absorbs 9.6 J of heat. What is the specific heat of Substance X in J/(g • mc005-3.jpgC)?

Answer 1

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$28$

Answer 2

Answer:

The specific heat of Substance X is $0.96 J/g ^oC$

Explanation:

Mass of the sample X = m = 5.0 g

Change in temperature of the substance $\Delta T=22^oC-20^oc=2^oC$

Specific heat of the substance = c

Heat absorbed by the substance = Q = 9.6 J

$Q=mc\DeltaT$

$9.6 J=5.0 g\times c\times 2^oC$

$c = 0.96 J/g ^oC$

The specific heat of Substance X is $0.96 J/g ^oC$