Question

A 5.0-m-diameter merry-go-round is turning with a 3.6 s period. What is the speed of a child on the rim?

Answer 1

Given: Time period of Merry-go-round = 3.6 s

Diameter of the ring = 5.0m⇒Radius=2.5m

Distance Travelled to complete 1 circle = 2πr = 2*π*2.5 = 5π

Time Taken to complete 1 circle = 3.6 s

Speed = Distance Travelled/time taken

⇒Speed = 5π/3.6 = 50*22/36*7 = 275/63 = 4.365079 m/s

Therefore, Spped of a child on the rim = 4.365079 m/s

Answer 2

Answer:

v=4.36

Explanation:

Diameter (d) = 5 meters

Period (T) = 3.6 seconds

Velocity (v) = Circumference (c) / Period (T)

Circumference = π x d

π x 5 / 3.6 = 15.707 / 3.6 = 4.36 m/s