Question

A 5.00 liter balloon of gas at 25 C is cooled to 0 C. What is the new volume (liters) of the balloon?

Answer 1

V1=5

T1=25+273=298K

T2=0+273=273K

V2=?

Using Charles law

V1/T1=V2/T2

5/298=V2/273

V2=5/298 x 273

V2=4. 58 Litre

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Answer 2

The new volume of the balloon is 4.58 Liters

Explanation:

Charles' Law: This law states that volume is directly proportional to the temperature of the gas at constant pressure and number of moles.

$V\propto T$     (At constant pressure and number of moles)

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where,

$V_1$ = initial volume of gas  = 5.00 L

$V_2$ = final volume of gas  = ?

$T_1$ = initial temperature of gas  = $25^0C=25+273=298K$

$T_2$ = final temperature of gas  = $0^0C=0+273=273K$

Putting in the values, we get:

$\frac{5.00}{298}=\frac{V_2}{273}$

$V_2=4.58L$

Learn More about Charles' Law

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