Question

A 5.00 mL sample of a solution of KCl (Mwt=74.6 g/mol) in water (Mwt=18.01 g/mol) weighs 5.20 g. The water is evaporated off leaving 0.26 g of residue. What is the mass of solution that would contain 1.00 g of KCl?

Answer 1

Answer:

20 g

Explanation:

Firstly , we will calculate density  of solution :

density = mass / volume

density = 5.20 / 5 = 1.04 g mL^-1

1 g KCl x 5 / 0.26 = 19.23 mL

Then , we use density to convert volume into mass :

19.23 x 1.04 / 1 = 20 g