A=√5+1/√3-1. b=√5-1/√3+1 , then (a+b)^2/(a-b)^2 equal to
Answers
Answered by
5
Answer:
Here.
a=√5+1/√3-1 and b=√5-1/√3+1
Now.
a+b=(√5+1/√3-1)+(√5-1/√3+1)
=(√15+√5+√3+1+√15-√5-√3 +1)/{(√3)^2-(1)^2}
=(2√15+2)/(3-1)
=2(√15+1)/2
=√15+1
(a+b)^2=(√15+1)^2
=(15+2√15+1)
=16+2√15
=2(8+√15)
and.
a-b=(√5+1/√3-1)-(√5-1/√3+1)
=(√15+√5+√3+1-√15+√5+√3-1)/{(√3)^2-(1)^2}
=(2√5+2√2)/(3-1)
=2(√5+√3)/2
=√5+√3
(a-b)^2=(√5+√3)^2
=5+2√15+3
=(8+2√15)
=2(4+√15)
{(a+b)^2}/{(a-b)^2}=2(8+√15)/2(4+√15)
=(8+√15)/(4+√15)
Similar questions