Question

A(5, 1 ) , B( 1, 5) and C (-3, -1) are the vertex of triangle ABC . find the length of the median AD

Answer 1

QUESTION:

A(5, 1 ) , B( 1, 5) and C (-3, -1) are the vertex of triangle ABC. Find the length of the median AD. (It is noted that point D sits on the line BC)

SOLUTION:

Find the coordinate of D:

D is the midpoint of BC

$\text {Coordinates of D} = \bigg( \dfrac{1+(-3)}{2} , \dfrac{5+ (-1)}{2} \bigg)$

$\text {Coordinates of D} = ( -1 , 2 )$

Find the length AD:

$\text {Length of AD = } \sqrt{(Y_2-Y_1)^2 + (X_2 - X_1)^2}$

$\text {Length of AD = } \sqrt{(1 - 2)^2 + (5 - (-1))^2}$

$\text {Length of AD = } \sqrt{(-1)^2 + (6)^2}$

$\text {Length of AD = } \sqrt{37}$

Answer: The length of AD is √37 units

Answer 2

Answer:

Step-by-step explanation:

CORDINATES OF D ARE(-1,2)

SO MEDIAN AD=√(5+1)²+(1+2)²

= √37 UNITS

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FROM THOSHITHA