A(5, 1); b(1, 5) and c(3, 1) are the vertices of abc. Find the length of median ad.
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as we know median through a divides the line bc in two equal halves
so , coordinates of d will be:
let its coordinates be (x,y)
given:- x1=1 , y1=5 , x2=3 , y2=1;
through mid point formula:
- for x coordinate
x = (x1 + x2 )/ 2
x = (1+3)/2
x = 4/2
x = 2
- for y coordinate :
y = (y1 + y2)/2
y = (5+1)/2
y = 6/2
y = 3
now the coordinates of d are (2,3)
now through distance formula :-
x1 = 5 , y1 = 1 , x2 = 2 , y2 = 3
ad^2 = (x2 - x1)^2 + (y2 - y1)^2
ad^2 = (-3)^2 +(2)^2
ad^2 = 9 + 4
taking square root both sides
we get : ad = _/ 13 units
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