Question

A,(5,1);b(1,5)and c(-3,-1) are the vertices of triangle abc.Find the length of median ad.

Answer 1

Find the coordinate of D:

D is the midpoint of BC

\text {Coordinates of D} = \bigg( \dfrac{1+(-3)}{2} , \dfrac{5+ (-1)}{2} \bigg)

\text {Coordinates of D} = ( -1 , 2 )

Find the length AD:

\text {Length of AD = } \sqrt{(Y_2-Y_1)^2 + (X_2 - X_1)^2}

\text {Length of AD = } \sqrt{(1 - 2)^2 + (5 - (-1))^2}

\text {Length of AD = } \sqrt{(-1)^2 + (6)^2}

\text {Length of AD = } \sqrt{37}