Question

A(5,1);B(1,5);C(-3,-1) are the vertices of a triangle ABC find the length of the median AD?

Answer 1

median is mid point of bc

let d(x,y)

x=1-3/2. y=5-1/2

x=-2/2. y=4/2

x=-1. y=2

so d(-1,2)

ad=√(5+1)²+(1-2)²

=√36+1

=√37.

Answer 2

Answer:

Step-by-step explanation:

first we have to calculate coordinate D by mid point

 x,y = x1+x2/2, y1+y2/2

  -3+1/2, 5-1/2

 -1,-2 = D

now median calculate by distance formula

√(x2 - x1) ²+ (y2 - y1)²

∴ √(5+1) ² + (1+2)²

   √ 36+9

  AD=    √45