(a/5. 1/b)= (3/5. 1/7) find the value of the a and b
Answers
Answer:
Answer: The length of AD is √37 units
Step-by-step explanation:
QUESTION:
A(5, 1 ) , B( 1, 5) and C (-3, -1) are the vertex of triangle ABC. Find the length of the median AD. (It is noted that point D sits on the line BC)
SOLUTION:
Find the coordinate of D:
D is the midpoint of BC
\text {Coordinates of D} = \bigg( \dfrac{1+(-3)}{2} , \dfrac{5+ (-1)}{2} \bigg)Coordinates of D=(
2
1+(−3)
,
2
5+(−1)
)
\text {Coordinates of D} = ( -1 , 2 )Coordinates of D=(−1,2)
Find the length AD:
\text {Length of AD = } \sqrt{(Y_2-Y_1)^2 + (X_2 - X_1)^2}Length of AD =
(Y
2
−Y
1
)
2
+(X
2
−X
1
)
2
\text {Length of AD = } \sqrt{(1 - 2)^2 + (5 - (-1))^2}Length of AD =
(1−2)
2
+(5−(−1))
2
\text {Length of AD = } \sqrt{(-1)^2 + (6)^2}Length of AD =
(−1)
2
+(6)
2
\text {Length of AD = } \sqrt{37}Length of AD =
37