Question

A(-5, 2) and B(4, 1). Find the equation of
the locus of point P, which is equidistant
from A and B.​

Answer 1

Step-by-step explanation:

A(-5, 2)=B(4, 1)

=-5a+2a=4b+b

=-7a=5b

=a/b=5+7

=ab=12

. :12ab

I think 12ab must be answer

Please mark as brainlist

Answer 2

Step-by-step explanation:

Let, P=(x, y)

Using Distance formula,

PA² = (x+5)²+(y-2)²

& PB² = (x-4)²+(y-1)²

Since, PA=PB

Therefore, PA²=PA²

i.e., (x+5)²+(y-2)²=(x-4)²+(y-1)²