A (5, 2), B (-3, 5) and vertex C is the point on the locus y = 2 + 3x + x^2, find the
equation of the locus of centroid G of ∆ABC.
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Answer:
let the centroid points be x,y
we can know distance is same from all sides or vertices means
ga=gb
use distance formula
root((5-x)^2+(2-y)^2)=root((-3-x)^2+(5-y)^2)
squaring on both sides
(5-x)^2+(2-y)^2=(-3-x)^2+(5-y)^2)
25+x^2-10x+4+y^2-4y=9+x^2+6x+25+y^2-10y
cancel x^2+y^2 on both sides
29-10x-4y=34+6x-10y
16x-6y+5=0
Step-by-step explanation:
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