A (5,3)and B (3,-2) are two fixed points find the equation of the locus of p so that the area of triangle pab is 9
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A (5,3) and B(3,-2) are two fixed points. Find the equation of the locus of P, so that the area of triangle PAB is 9.
Let say Point P ( x , y)
P (x , y) , A( 5 , 3) & B (3 , -2)
Area of Δ PAB = (1/2)(| Px(Ay - By) + Ax(By - Py) + Bx(Py - Ay) |)
=> 9 = (1/2) | (x(3 -(-2)) + 5(-2 - y) + 3(y - 3)|
=> 18 = | 5x -10 -5y + 3y - 9|
=> 18 = | 5x - 2y -19 |
Case 1 : 5x - 2y -19 = 18
=> 5x - 2y = 37
Case 2 5x - 2y -19 = -18
=> 5x - 2y = 1
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