Question

πa^5-π^3ab^2 factorise

Answer 1

πa^5-π³ab²

TAKE COMMON OF π,A

πa [a⁴-π²b²]

πa [(a²)²-(πb)²]

πa(a²+πb) (a²-πb)

BY USING IDENTITY

a²-b²= (a+b) (a-b)

Answer 2

πa^5-π^3ab^2

πa(a^4-π^2 b^2)

πa[(a^2) ^2-(πb) ^2]

πa(a^2+πb) (a^2-πb)