Math, asked by VIGYAS, 7 months ago

A 5.4-V battery is connected to a bulb whose resistance is 3.1Ω. What is the current through the bulb?​


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Answers

Answered by aruanu1815
6

Answer:

Given:-

☛Voltage of battery = 5.4 V

☛Resistance = 3.1Ω

Find:-

☛Current produces-?

Solution:-

☛According to ohm's law,

\boxed{\bf{V=IR}}

where,

v= voltage

I= current

R= Resistance

Put values,

\sf{\implies 5.4 = I \times 3.1 }

\sf{\implies I= \dfrac{5.4}{3.1}}

\sf{ \implies  I= 1.74}

Therefore , Current Produces through bulb is 1.74 A.

(Unit of Current = ampere (A))

Answered by MoonlightPhoenix
4

Question Given :

  • A 5.4-V battery is connected to a bulb whose resistance is 3.1Ω. What is the current through the bulb?

Required Solution :

Value Given to us :

  • ⟿ Potential difference = 5.4 V

  • ⟿ Resistance = 3.1 Ω

Formula Used Here :

  • ⟿ V = I × R

Putting Value in Formula :

  • V = I × R

  • ⟿ 5.4 = I × 3.1

  • ⟿ I = 1.74 ( Approximately)

Therefore :

  • The current through the bulb will be 1.74 Ampere

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