Question

A 5.4-V battery is connected to a bulb whose resistance is 3.1Ω. What is the current through the bulb?​

Answer 1

Answer:

Given:-

☛Voltage of battery = 5.4 V

☛Resistance = 3.1Ω

Find:-

☛Current produces-?

Solution:-

☛According to ohm's law,

V=IR

where,

v= voltage

I= current

R= Resistance

Put values,

5.4 = I 3.1 }⟹5.4=I×3.1

I= {5.4}{3.1}}⟹I=

3.1

5.4

I= 1.74}⟹I=1.74

Therefore , Current Produces through bulb is 1.74 A.

(Unit of Current = ampere (A))

Answer 2

$\star\small\sf\underline\blue{Given:-}$

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• A 5.4 V battery is connected to a bulb whose resistance is 3.1Ω.

______________________

$\star\small\sf\underline\blue{Find \: Out:-}$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

• The required current produce through the bulb = ?

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$\star\small\sf\underline\blue{Solution:-}$

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$\footnotesize\bold{\underline{\underline{\sf{\red{Formula\:used:-}}}}}$

${\underline{\boxed{\sf{Voltage = Current \times Resistance }}}}$

$\footnotesize\bold{\underline{\underline{\sf{\red{Putting\:the\:values:-}}}}}$

$\leadsto \sf \: 5.4 = Current \times 3.1 \\ \\ \leadsto \sf \: Current = \cancel\dfrac{5.4}{3.1} \\ \\ \leadsto \sf \: Current = 1.74\:Ampere$

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$\star\small\sf\underline\blue{AnswEr:-}$

• The required current produce through the bulb is 1.74 Ampere.