A 5.5kg rifle fires a 1.1 grams bullet with a muzzle velocity of 450 m/sec.what is the recoil velocity of the rifle?
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Answered by
1
m1 x v1 = m2 x v2
5500 x (- z) = 1.1 x 450
z = (- 0.09) m/sec
z is the recoil velocity of the rifle
If it helps you then please mark it as brainliest
5500 x (- z) = 1.1 x 450
z = (- 0.09) m/sec
z is the recoil velocity of the rifle
If it helps you then please mark it as brainliest
ayesha63:
what will be value of 2nd velocity?
what will be value of 2nd velocity?
what will be value of 2nd velocity?
what is 2nd velocity?
is it of the rifle
is it okay now?
5.5 kg = 5500 grams
I already know that
first see my answer then tell me
Oh I didn’t refreshed my page
Answered by
2
Momentum is conserved
Initial momentum = Final momentum
0 = Momentum of rifle + Momentum of bullet
0 = Mv + mu
v = - (mu) / M
= - (1.1 × 10^-3 kg × 450 m/s) / (5.5 kg)
= - 0.09 m/s
Here negative sign indicates that gun recoils in the direction opposite to that of bullet.
Recoil velocity of gun is 0.09 m/s
Initial momentum = Final momentum
0 = Momentum of rifle + Momentum of bullet
0 = Mv + mu
v = - (mu) / M
= - (1.1 × 10^-3 kg × 450 m/s) / (5.5 kg)
= - 0.09 m/s
Here negative sign indicates that gun recoils in the direction opposite to that of bullet.
Recoil velocity of gun is 0.09 m/s
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