A 5.5kg rifle fires a 1.1 grams bullet with a muzzle velocity of 450 m/sec.what is the recoil velocity of the rifle?
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m1 x v1 = m2 x v2
5500 x (- z) = 1.1 x 450
z = (- 0.09) m/sec
z is the recoil velocity of the rifle
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5500 x (- z) = 1.1 x 450
z = (- 0.09) m/sec
z is the recoil velocity of the rifle
If it helps you then please mark it as brainliest
ayesha63:
what will be value of 2nd velocity?
Answered by
2
Momentum is conserved
Initial momentum = Final momentum
0 = Momentum of rifle + Momentum of bullet
0 = Mv + mu
v = - (mu) / M
= - (1.1 × 10^-3 kg × 450 m/s) / (5.5 kg)
= - 0.09 m/s
Here negative sign indicates that gun recoils in the direction opposite to that of bullet.
Recoil velocity of gun is 0.09 m/s
Initial momentum = Final momentum
0 = Momentum of rifle + Momentum of bullet
0 = Mv + mu
v = - (mu) / M
= - (1.1 × 10^-3 kg × 450 m/s) / (5.5 kg)
= - 0.09 m/s
Here negative sign indicates that gun recoils in the direction opposite to that of bullet.
Recoil velocity of gun is 0.09 m/s
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