Question

a 5.5m long ladder is leaned against the wall to a height of 4.4m.find the distance between the wall and the foot of the ladder
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Answer 1

Answer:

$\fbox \green {The distance between the wall and ladder is √10.89 }$

Step-by-step explanation:

Here u go with your answer:-

We know that In Pythagoras theorem:-

Hypotenuse ² = Base² + Perpendicular ²

Here , let the length of ladder be AB.

And the height of the wall be AC

And the distance between the ladder and the wall be BC.

And let's take AB = HYPOTENUSE

AC = PERPENDICULAR

BC = BASE

Now let's substitute the respective value in the Above mentioned formula....

$</p><p>[tex]Hypotenuse ² = Base² + Perpendicular ²</p><p>[tex]Hypotenuse ² = Base² + Perpendicular ²$

${(5.5)}^{2} = {bc}^{2} + {(4.4)}^{2} \\ 30.25 = {bc}^{2} + 19.36 \\ 30.25 - 19 .36 = {bc}^{2} \\ 10.89 = {bc}^{2} \\ \sqrt{10.89} = bc \: answer$

Hence the distance between the wall and the ladder is

$\sqrt{10.89} cm$

Answer 2

Step-by-step explanation:

we can used Pythagoras theorem here

(length of ladder) ² = (height of wall) ² + (distance

between wall and the ladder foot)²

(5.5)²=(4.4)²+(distance between wall and the

ladder foot)²

distance between wall and the ladder foot =

(30.25-19.36)½

distance between wall and the ladder foot = 3.3