Question

A (-5,7), B (-4, -5), C (-1, -6), D (4,5) If there are four vertices of a quadrilateral, what is the area of ​​quadrilateral ABCD?​

Answer 1

Answer:

Area quadrilateral ABCD=72 sq.cm

Step-by-step explanation:

given,

A (-5,7)=(x1,y1)

B (-4, -5)=(x2,y2)

C(-1, -6)=(x3,y3)

D (4,5)=(x4,y4)

Area of quadrilateral ABCD is = (1/2) ⋅ {(x1y2 + x2y3 + x3y4 + x4y1) - (x2y1 + x3y2 + x4y3 + x1y4)}

=(1/2) {25+24-5+28} - {-28+5-24-25}

=(1/2) {72} - {-72}

=(1/2){72+72}

=144/2

=72sq.cm

Hope you understand

Please make it a brainlist answer