Question

A(5-8)andB(3-6)
I NEED HELP DISTANCE FOURMULA

Answer 1

Step-by-step explanation:

Given :-

The points are A(5,-8) and B(3,-6)

To find :-

Find the distance between the two points ?

Solution :-

Given points are A(5,-8) and B(3,-6)

Let (x1, y1) = A(5,-8) => x1 = 5 and y1 = -8

Let (x2,y2) = B(3,-6) => x2 = 3 and y2 = -6

We know that

The distance between two points (x1, y1) and

(x2, y2) is √[(x2-x1)²+(y2-y1)²] units

On substituting these values in the above formula then

=> AB =√[(3-5)²+(-6-(-8))²]

=> AB =√[(-2)²+(-6+8)²]

=> AB =√[4+(2)²]

=> AB = √(4+4)

=> AB =√8

=> AB =√(2×2×2)

=> AB = 2√2 units

Answer:-

The distance between two points A and B is AB =√8 units or 2√2 units

Used formulae:-

Distance formula:-

The distance between two points (x1, y1) and (x2, y2) is √[(x2-x1)²+(y2-y1)²] units

Answer 2

Answer:

AB =  $\bf{2\sqrt{2}}$units

Step-by-step explanation:

Diagram :

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines \qbezier(0,0)(0,0)(5,0) \put(-.5,-.5){\bf{A (5,-8)}} \put(0.01,0){\circle*{.15}} \put(4.5,-.5){\bf{B (3,-6)}} \put(5,0){\circle*{.15}} \put(1.3,-1.6){\boxed{\bf{@LetsHelp123}}}\end{picture}$

*Please see the attached image if its not visible.

Given co-ordinates :

• A(5,-8) = (x₁,y₁)
• x₁ = 5 , y₁ = -8
• B(3,-6) = (x₂,y₂)
• x₂ = 3 , y₂ = -6

Applying Distance formula now,

$AB = \sqrt{(x_2-x_1)^2 + (y_2 - y_1)^2}$

$\implies AB = \sqrt{(3 - 5)^2 + [-6 - (-8)]^2 }$

$\implies AB = \sqrt{(-2)^2 + (-6 +8)^2}$

$\implies AB = \sqrt{4 + (2)^2}$

$\implies AB = \sqrt{4+4}$

$\implies AB = \sqrt{8}$

$\implies AB = \sqrt{2 \times 2 \times 2}$

$\implies AB = 2\sqrt{2}$

∴ AB =  $\bf{2\sqrt{2}}$units

Thanks !