Math, asked by tejnayak82, 7 hours ago

a 5. A particle starts from rest at a distance b from a fixed point, under the action of a towards force through the fixed point, the law of which at a distance x isu (1-9tow the point when x > a butui from the same point when x < a ; prove that X X the particle will oscillate through a space (62 - a)/b.​

Answers

Answered by sonayadav6508
0

Answer:

Step-by-step explanation:

Given,  

s=t  

2

+at−b+17

After 5s,  

[  

dt

ds

]  

t=5

=[2t+a]  

t=5

=0  

⇒a=−10

At t=5s,s=25 units

∴25=5  

2

+5a−b+17        [∵s=25 and t=5]

⇒25=25+5(−10)−b−b+17

⇒50−17=−b

⇒b=−33

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