Question

A
5. ABC and DBC are two isosceles triangles on the
same base BC (see Fig. 7.33). Show that
LABD=LACD.
​

Answer 1

Given:

∆ABC is isosceles

so,AB=AC

∆DBC is isosceles

so,DB=DC

To prove:∆ABD=∆ACD

Proof:

Let us join AD.

We take ∆ABD and ∆ACD,

In ∆ABD and ∆ACD,

AB=AC

BD=CD

AD=AD

•°•∆ABD=~∆ACD

∆ABD=∆ACD

Hence proved.