Math, asked by Chandu6626, 11 months ago

A 5 age is six times B's age. Four years
hence, the age of A will be four times
B's age. Find the present ages, in years,
Of A and B.

Answers

Answered by martandgupta401
1
  1. Answer:  Step-by-step explanation: AGE OF A = X AGE OF B = Y AGE OF A = 5 (AGE OF B) X = 5Y                                 ............1 FOUR YEAR HENCE MEANS AFTER FOUR YEARS X+4 = 4(Y+4) X+4 = 4Y+16 X-4Y = 16-4 X-4Y = 12                            ............2  X-5Y=0 X-4Y=12 -_+__-____ -Y=-12                                                                       (ON USING ELEMINATION METHOD) Y = 12 X=5*12 X=60
Similar questions