A 5–ampere fuse wire can withstand a maximum power of 1 watt in the circuit. The resistance of the fuse wire is(a) 0.04 Ω(b) 0.2 Ω(c) 5 Ω(d) 0.4 Ω
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According to the Ohm's law of electricial resistance,we get the following mathematical formula;
P(power)=I²(electricial current) R (electrical resistance)
P=I²R [we also have to apply this particular formula to calculate the resistance of the fuse wire]
1=5²R [according to the data mentioned in the question]
R=1/25
R=0.04 Ohm
That's why the correct answer of this question is option a.
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