a 5 capacitor is charged to 12 V the positive plate is now connected to negative plate and vice versa calculate heat devloped in connection wires
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Final Answer : 1.44 * 10^(-3) J
According to me, Capacitance is 5uF as I cant expect any huge value of capacitance.
Q : A 5uF capacitor is charged to 12 V. The positive plate of this capacitor is now connected to the negative terminal of a 12 V battery and vice - versa.
Calculate the heat developed in the connecting wires.
Understanding and Steps :
1) When the capacitor is connected with battery, the charge appears on plates such that + terminal of battery is connected to capacitor having + charge and vice versa.
2) Then, Capacitor is disconnected and again connected with the same battery with opposite polarity.
(See Circuit Diagram in pic)
3) Total Charge flown from battery = Q - (-Q) = 2Q
4) A charge 2Q passes through the battery from the negative to the positive terminal.
=> Work done by battery =(2Q) * V
= 2CV^2
5) The Energy stored in the capacitor is the same in both the processes.
6) So, Entire work done will seen as heat in connecting wires.
Heat Produced = 2 CV^2
= 2 * 5 uF * (12)^2
= 10* 10^(-6 ) * 144
= 1.4 * 10^(-3) J
According to me, Capacitance is 5uF as I cant expect any huge value of capacitance.
Q : A 5uF capacitor is charged to 12 V. The positive plate of this capacitor is now connected to the negative terminal of a 12 V battery and vice - versa.
Calculate the heat developed in the connecting wires.
Understanding and Steps :
1) When the capacitor is connected with battery, the charge appears on plates such that + terminal of battery is connected to capacitor having + charge and vice versa.
2) Then, Capacitor is disconnected and again connected with the same battery with opposite polarity.
(See Circuit Diagram in pic)
3) Total Charge flown from battery = Q - (-Q) = 2Q
4) A charge 2Q passes through the battery from the negative to the positive terminal.
=> Work done by battery =(2Q) * V
= 2CV^2
5) The Energy stored in the capacitor is the same in both the processes.
6) So, Entire work done will seen as heat in connecting wires.
Heat Produced = 2 CV^2
= 2 * 5 uF * (12)^2
= 10* 10^(-6 ) * 144
= 1.4 * 10^(-3) J
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