Question

a 5 centimetre tall object is placed perpendicular to the principal axis of a convex lens of focal length 18 cm at a distance of 12 cm from it. use lens formula to determine the posistion size and nature of the image formed​

Answer 1

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• F = 18cm
• u = -12cm
• Using lens formula
• $\frac{1}{v} = \frac{1}{f} + \frac{1}{u}$
• $\frac{1}{v} = \frac{1}{18} - \frac{1}{12}$
• $v = - 36cm$
• $m = \frac{v}{u} = \frac{ - 36}{ - 12} = 3$
• Image is Magnified ,virtual and erect.