A 5-cm high object is placed 5 cm from a 15-cm focal length converging lens. Determine the image distance, the magnification of the image, the image height and the properties of the image
Answers
Correct Question: A 5-cm high object is placed 5 cm from a 15-cm focal length converging lens. Determine the image distance, the magnification of the image, the image height and the properties of the image
Given:
The focal length (f) = 15 cm
The plus sign indicates that the focal point is real or the rays pas through the point.
The object height (ho) = 5 cm
The object distance (do) = 5 cm
Wanted : the image distance, the magnification of image, the image height and the properties of image
Explanation :
The image distance (di) :
1/di = 1/f – 1/do = 1/15 – 1/5 = 1/15 – 3/15 = -2/15
di = -15/2 = -7.5 cm
The minus sign indicates that the image is virtual or the rays do not pas through the image.
The magnification of image (m) :
m = – di / do = -(-7.5)/5 = 7.5/5 = 1.5
The plus sign indicates that the image is upright.
The image height (hi) :
m = hi / ho
hi = m ho = (1.5)5 = 10/3 = 7.5 cm
The plus sign indicates that the image is upright.
The properties of the image
–> virtual
–> upright
–> The image greater than the object
–> The image distance is greater than the object distance
hope it help you
A 5-cm high object is placed 5 cm from a 15-cm focal length converging lens. Determine the image distance, the magnification of the image, the image height and the properties of the image
hope it help you mate