Question

A 5-cm high object is placed 5 cm from a 15-cm focal length converging lens. Determine the image distance, the magnification of the image, the image height and the properties of the image​

Answer 1

Correct Question: A 5-cm high object is placed 5 cm from a 15-cm focal length converging lens. Determine the image distance, the magnification of the image, the image height and the properties of the image

Given:

The focal length (f) = 15 cm

The plus sign indicates that the focal point is real or the rays pas through the point.

The object height (ho) = 5 cm

The object distance (do) = 5 cm

Wanted : the image distance, the magnification of image, the image height and the properties of image

Explanation :

The image distance (di) :

1/di = 1/f – 1/do = 1/15 – 1/5 = 1/15 – 3/15 = -2/15

di = -15/2 = -7.5 cm

The minus sign indicates that the image is virtual or the rays do not pas through the image.

The magnification of image (m) :

m = – di / do = -(-7.5)/5 = 7.5/5 = 1.5

The plus sign indicates that the image is upright.

The image height (hi) :

m = hi / ho

hi = m ho = (1.5)5 = 10/3 = 7.5 cm

The plus sign indicates that the image is upright.

The properties of the image

–> virtual

–> upright

–> The image greater than the object

–> The image distance is greater than the object distance

hope it help you

Answer 2

A 5-cm high object is placed 5 cm from a 15-cm focal length converging lens. Determine the image distance, the magnification of the image, the image height and the properties of the image

hope it help you mate