A 5 cm long object is placed in front of a concave mirror of radius of
curvature 40 cm. The distance of object from mirror is 40 cm. Find the
distance and size of the image.
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Answer:U=-200cm(since 20m)
h=5cm
r=40cm
So f= -20cm(since f=r/2 & concave mirror)
Now using mirror formula--
1/u+1/v=1/f
1/v=1/f-1/u
1/v=1/-20–(1/-200)
1/v=-9/200
v=200/-9=-22.2cm
So position of the image is 22.2cm to the left of the mirror.
Now,
magnification m=-v/u
h'/h=-v/u
h'/5=-(-22.2/-200)
h'=-(111/200)
h'=-0.56
Hence, sizeof the image is 0.56cm and is real and inverted.
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