a 5 cm object is placed perpendicular to the principal axis of lens of power +5D the distance of the object from the lens is 30 cm. find the position,nature and size of the image formed.
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position of image = 60cm
size of image = 10cm [ in magnitude]
nature = real , inverted and enlarged.
power of lens, P = + 5D
so, focal length of lens, f = 100/P cm = 100/5 = 20cm
object distance from the pole of Lens, u = -30cm
using formula, 1/v - 1/u = 1/f
⇒1/v - 1/-30 = 1/20
⇒1/v = 1/20 - 1/30 = 10/600 = 1/60
⇒v = 60cm
hence, image is formed 60cm away from the lens (same side of object).
magnification, m = v/u = height of image/height of object
⇒60cm/-30cm = height of image/5cm
⇒-2 × 5cm = height of image
⇒height of image = -10cm
hence, size of image is greater than size of object. image is real, inverted and enlarged.
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