A 5 cm tall light bulb is placed at a distance of 30 cm from a concave mirror having a focal length 0f 20 cm.
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Answer:
Given: An object of 5cm tall is placed at a distance of 10cm from a concave mirror of radius of curvature 30cm
To find: the nature, position and size of the image and draw the ray diagram to represent the above case.
Solution:
According to the given criteria,
Let height of the image be h
i
and
Height of the object, h
o
=5cm
Object distance, u=−10cm
Radius of curvature, R=−30cm
We know, focal length, f=
2
R
=
2
30
=−15cm
Now applying mirror formula, we get
f
1
=
v
1
+
u
1
⟹
v
1
=
f
1
−
u
1
⟹
v
1
=
−15
1
−
−10
1
⟹
v
1
=
150
−10+15
=
150
5
⟹v=30cm
Position of the image is behind the mirror at the distance of 30 cm
Magnification, m=−
u
v
=
h
o
h
i
⟹−
−10
30
=
5
h
i
⟹h
i
=3×5=15cm
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