A 5 cm tall object is placed at a distance of 30 cm from a convex mirror of focal length 15 cm.Find the position,size and nature of the image formed
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Answer:
In convex mirror h1= +5
object distance (u)= -30
focal length (f)=+15
To find image distance (v),
By mirror formula,
1/F = 1/V +1/U
1/15= 1/V + 1/(-30)
1/15 +1/30 =1/V
2+1/30 = 1/V
3/30=1/10 = 1/V
[V = 10]
virtual image and form behind the mirror.
TO FIND NATURE,
We will find h2
( h2/h1 = -v/u) formula
h2/5 = -10/-30
h2/5= 1/3
h2 = 1/3 × 5
[h2= +1.66]
h2 is positive so image will be ERECT and VIRTUAL.
Answered by
1
Answer:
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Explanation:
u= -30cm and f=15cm. We get v as +10cm. Positive sign indicates that it is a virtual image. Therefore size of image would be 5/3 cm
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