A 5 cm tall object is placed on the principal axis of a concave mirror of focal length 10 cm at a distance of 15 cm from it .
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Answered by
3
Answer:
Step-by-step explanation:
H=5cm
u = -15cm
F=10
put in formula
1/v+1/u=1/f
1/v+1/-15=1/10
1/v=1/10+1/15
1/v=5/30
v=6
size of imag e=-v/u
=-6/-15
Step-by-step explanation:
H=5cm
u = -15cm
F=10
put in formula
1/v+1/u=1/f
1/v+1/-15=1/10
1/v=1/10+1/15
1/v=5/30
v=6
size of imag e=-v/u
=-6/-15
Answered by
0
Answer:
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Step-by-step explanation:
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