a 5 cm tall object is placed perpendicular to principal axis of a convex lens of focal length 10 cm if the object is placed 30 cm away from lens find the position size and nature of image
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focal length is + ve for convex lens so we can find image distance ... v = 15cm .. image is real or inverted
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height of object=h0=5cm
focal length of lens=10cm
object distance=-30cm
1/f=1/v-1/u
=1/10-1/30
=3-1/30
2/30
v=30/2= 15cm
m=v/u
m=15/-30 =-1/2= -0.5cm
hi=m x ho
=-0.5x 5
= -2.5cm
object is placed beyond C and image formed is in between F and c.
Inverted, real and diminished.
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