A 5 cm tall object is placed perpendicular to the principal axis of a lens of power + 5d.The distance of the object from the lens is 30 cm
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Dear Student,
◆ Complete question -
Q. A 5 cm object is placed perpendicular to the principal axis of lens of power +5D the distance of the object from the lens is 30 cm. Find the position, nature and size of the image formed.
● Answer -
Image will be formed at 60 cm on right of size 10 cm and is real, inverted and magnified.
◆ Explaination -
# Given -
P = +5 D
u = -30 cm
h1 = +5 cm
# Solution -
Focal length is -
f = 1/P
f = 1/5
f = 0.2 m
f = 20 cm
According to lens formula -
1/f = 1/v - 1/u
1/20 = 1/v - 1/(-30)
v = +60 cm
Magnification is -
M = -v/u
M = -60/(-30)
M = +2
Size of the image is -
M = h2/h1
2 = h2/5
h2 = 5×2
h2 = 10 cm
So the image will be formed at 60 cm on right of size 10 cm and is real, inverted and magnified.
Thanks dear...
Answered by
1
10cm is the correct answer
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