A 5 cm tall object is placed perpendicular to the principal axis of a convex lens of focal- length 20 cm. The distance of the object from the len is 30 cm. Find the: (i) position (ii) nature (iii) size of the image formed.
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Explanation:
Given object size = 5 cm
u = -30 cm
f = 20 cm, v = ?
Using the lens formula 1/f = 1/v-1/u
We have 1/v = 1/u + 1/f = 1/-30 + 1/20 = -2+3/60 = 1/60
===> 1/v = 1/60
Therefore v = 60cm
Magnification v/u = 60/-30 = -2
Magnification = Image size/Object size
$h _{ i }$/$h _{ o }$ = -2
$h _{ i }$/5 = -2
$h _{ i }$ = -2x5 = -10 cm
The image is real inverted and magnified.
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