a 5 cm tall object is placed perpendicular to the principal axis of concave lens of focal lenghth 20 cm the distance of the object from the lens is 30cm
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Explanation:
Given
u=-30cm
f=20cm
1/v-1/u=1/f
1/v -(1/-30) =1/20
1/v=1/20-1/30
1/v=3-2/60
v=60cm
Image is real and inverted.
m=v/u
where, v=height of image
u= height of object
60/-30=h/5
60×5/-30=h
-10cm=h
Height of image is 10 cm.
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