Question

a 5 cm tall object is placed perpendicular to the principal axis of concave lens of focal lenghth 20 cm the distance of the object from the lens is 30cm​

Answer 1

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Answer 2

Explanation:

Given

u=-30cm

f=20cm

1/v-1/u=1/f

1/v -(1/-30) =1/20

1/v=1/20-1/30

1/v=3-2/60

v=60cm

Image is real and inverted.

m=v/u

where, v=height of image

u= height of object

60/-30=h/5

60×5/-30=h

-10cm=h

Height of image is 10 cm.