Question

: A 5 cm tall object is placed
perpendicular to the principal axis of a convex lens
of focal length 20 cm. The distance of the object from
the lens is 30 cm. Find the (i) Position, and (ii) nature
of the image formed.?​

Answer 1

Answer:

According to the question:

Object distance, u=−12 cm

Focal length, f=18 cm (since, convex lens)

Let the Image distance be v.

By lens formula:

v1−u1=f1[4pt]

⇒v1−−12 cm1=18 cm1[4pt]

⇒v1=−12 cm1+18 cm1[4pt]

⇒v1=36 cm−3+2[4pt]

⇒v1=−36 cm1[4pt]

∴v=−36 cm

Thus, image is obtained at 36 cm on the same side of the mirror as the object.

Now,

Height of object, h1=5 cm

Magnification, m=h1h2

Answer 2

Answer:

1/v-1/u=1/f

1/v-1/(-30)=1/20

1/v=1/60cm

v=60cm=poition

since image is in +ve then nature is virtual & erect

Explanation:

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