A 5 cm tall object is placed perpendicular to the principal axis of a concave lens of focal- length 20 cm. The distance of the object from the len is 30 cm. Find the: (i) position (ii) nature (iii) size of the image formed.
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Answer:
h= 5
f= 20
u = -30
v = ?
h' = ?
1/u + 1/v = 1/f
1/v = 1/f - 1/u
= 1/20 - 1/-30
= 1/20 - 1/30
= 3 - 2/60
= 1/60
v = 60
image is at 60 cm from the lens, and it is virtual.
m = v/u
h'/h = v/u
h'/5 = 60/-30
h' = -10 cm
Size is diminished.
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