Question

A 5 cm tall object placed perpendicular to principal axis of convex lens of focal length 18 cm at the lens at the distance of 12 cm from it. use lens formula to find position, size and nature of the image

Answer 1

so using sign convention

our object height = 5cm

focal length = 18cm

u = -12cm

therefore image distance =

1/v + 1/12 = 1/18 hence 1/v = -1/36

v = -36cm

nature of image is virtual

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