Question

A 5 digit number xy235 is divisible by 3 such that x + y < 5 where x and y are digits, then find the possible values of (x, y)?

Answer 1

As we know , that a number is divisible by 3 if the sum of all its digits is divisible by 3 .

Now,
2+3+5=10
and
x+y<5

Then the sum of x+y has to be 1,2,3 or 4.
Now we have to calculate which one will agree with the condition.
10+1=11 , 11 is not divisible by 3
10+2=12 , 12 is divisible by 3 .

Then , x+y = 2

Then the value :
x=1
y=1


Hope it helps :)

Answer 2

Answer: There are 5 possible numbers.

X+Y < 5

X+Y+2+3+5=10+X+Y

X=1 , Y=1

X=2 , Y=0

X=2 ,Y=3

X=3 ,Y=2

X=5 ,Y=0

The numbers are

11235

20235

23235

32235

50235

Hope it helps! !

Step-by-step explanation: