a 5. If a2x-3.b2x = a x.bSx, prove that 3loga = xlog b
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3−x
b
5x
=a
x+5
b
3x
Apply logarithm on both sides
⟹(3−x)loga+5xlogb=(x+5)loga+3xlogb
⟹3loga−xloga+5xlogb=xloga+5loga+3xlogb
⟹x(2logb−2loga)=2loga
⟹xlog(
a
b
)=loga
Hence Proved
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