A 5 kg ball is dropped from a height of 10m. (a) Find the initial potential energy of the ball
(b) Find the kinetic energy just before it reaches the ground and (c) Calculate the velocity
before it reaches the ground
Answers
a) It is given that :-
- Mass of ball = 5kg
- Height from dropped = 10m
- Potential energy = ?
Now we know that potential energy of a body is :
Let's take the value of g as 10 for easy calculation.
Therefore the Initial potential energy of ball is 500J.
b) Now when it reaches the ground then it's height will be 0 and thus potential energy will also be 0 , Now according to law of conservation of energy it's potential energy will convert into it's kinetic energy, Therefore the kinetic energy of ball just before reaching the ground will be 500J.
c) Now We know it's kinetic energy is = 500 J.
This can be said that :-
After inputting the values we get :-
Therefore we get velocity of body to be 14.14 m/s
_____________________________________
BY SCIVIBHANSHU
THANK YOU
STAY CURIOUS
To appreciate me you can mark my answer Brainliest.
Answer:
Explanation:
a) It is given that :-
Mass of ball = 5kg
Height from dropped = 10m
Potential energy = ?
Now we know that potential energy of a body is :
Let's take the value of g as 10 for easy calculation.
Therefore the Initial potential energy of ball is 500J.
b) Now when it reaches the ground then it's height will be 0 and thus potential energy will also be 0 , Now according to law of conservation of energy it's potential energy will convert into it's kinetic energy, Therefore the kinetic energy of ball just before reaching the ground will be 500J.
c) Now We know it's kinetic energy is = 500 J.
This can be said that :-
After inputting the values we get :-
Therefore we get velocity of body to be 14.14 m/s
_____________________________________
THANK YOU
STAY CURIOUS
To appreciate me you can mark my answer Brainliest.