Physics, asked by guptamanay, 4 months ago

A 5 kg ball is dropped from a height of 10m. (a) Find the initial potential energy of the ball

(b) Find the kinetic energy just before it reaches the ground and (c) Calculate the velocity

before it reaches the ground​

Answers

Answered by SCIVIBHANSHU
29

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a) It is given that :-

  • Mass of ball = 5kg
  • Height from dropped = 10m
  • Potential energy = ?

Now we know that potential energy of a body is :

pe = mgh

Let's take the value of g as 10 for easy calculation.

pe = 5 \times 10 \times 10

pe = 500j

Therefore the Initial potential energy of ball is 500J.

b) Now when it reaches the ground then it's height will be 0 and thus potential energy will also be 0 , Now according to law of conservation of energy it's potential energy will convert into it's kinetic energy, Therefore the kinetic energy of ball just before reaching the ground will be 500J.

c) Now We know it's kinetic energy is = 500 J.

This can be said that :-

500j =  \frac{1}{2}  \times m \times  {v}^{2}

After inputting the values we get :-

500 =  \frac{1}{2}  \times 5 \times  {v}^{2}

 \frac{500 \times 2}{5}  =  {v}^{2}

200 =  {v}^{2}

v =  \sqrt{200}  = 14.14

Therefore we get velocity of body to be 14.14 m/s

_____________________________________

BY SCIVIBHANSHU

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Answered by Anonymous
3

Answer:

Explanation:

a) It is given that :-

Mass of ball = 5kg

Height from dropped = 10m

Potential energy = ?

Now we know that potential energy of a body is :

Let's take the value of g as 10 for easy calculation.

Therefore the Initial potential energy of ball is 500J.

b) Now when it reaches the ground then it's height will be 0 and thus potential energy will also be 0 , Now according to law of conservation of energy it's potential energy will convert into it's kinetic energy, Therefore the kinetic energy of ball just before reaching the ground will be 500J.

c) Now We know it's kinetic energy is = 500 J.

This can be said that :-

After inputting the values we get :-

Therefore we get velocity of body to be 14.14 m/s

_____________________________________

THANK YOU

STAY CURIOUS

To appreciate me you can mark my answer Brainliest.

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