A 5 kg ball when falls through a height of 20 m acquires a speed of 10 m/s. Find the work done by air resistance
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Answered by
5
Answer:
speed gained in absence of air is given by
v^2 - 0^2 = 2×10 ×20
v^2 = 400m/s
speed gained in presence of air is given by
v^2= 10^2=100
so work done by air
1/2 × 5 × (100-400) = -150×5= - 750 joule
clearly the air resistance tries to decrease the speed of ball hence work done by it must be negative.
Answered by
4
Hi
W= - 750 J
Hope you understood
Thank you!!
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